Integrand size = 23, antiderivative size = 203 \[ \int \frac {1}{x^3 (1+x)^{5/2} \left (1-x+x^2\right )^{5/2}} \, dx=\frac {26}{27 x^2 \sqrt {1+x} \sqrt {1-x+x^2}}+\frac {2}{9 x^2 \sqrt {1+x} \sqrt {1-x+x^2} \left (1+x^3\right )}-\frac {91 \left (1+x^3\right )}{54 x^2 \sqrt {1+x} \sqrt {1-x+x^2}}-\frac {91 \sqrt {2+\sqrt {3}} \sqrt {1+x} \sqrt {\frac {1-x+x^2}{\left (1+\sqrt {3}+x\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {1-\sqrt {3}+x}{1+\sqrt {3}+x}\right ),-7-4 \sqrt {3}\right )}{54 \sqrt [4]{3} \sqrt {\frac {1+x}{\left (1+\sqrt {3}+x\right )^2}} \sqrt {1-x+x^2}} \]
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Time = 0.05 (sec) , antiderivative size = 203, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {929, 296, 331, 224} \[ \int \frac {1}{x^3 (1+x)^{5/2} \left (1-x+x^2\right )^{5/2}} \, dx=-\frac {91 \sqrt {2+\sqrt {3}} \sqrt {x+1} \sqrt {\frac {x^2-x+1}{\left (x+\sqrt {3}+1\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {x-\sqrt {3}+1}{x+\sqrt {3}+1}\right ),-7-4 \sqrt {3}\right )}{54 \sqrt [4]{3} \sqrt {\frac {x+1}{\left (x+\sqrt {3}+1\right )^2}} \sqrt {x^2-x+1}}+\frac {26}{27 x^2 \sqrt {x+1} \sqrt {x^2-x+1}}-\frac {91 \left (x^3+1\right )}{54 x^2 \sqrt {x+1} \sqrt {x^2-x+1}}+\frac {2}{9 x^2 \sqrt {x+1} \sqrt {x^2-x+1} \left (x^3+1\right )} \]
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Rule 224
Rule 296
Rule 331
Rule 929
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {1+x^3} \int \frac {1}{x^3 \left (1+x^3\right )^{5/2}} \, dx}{\sqrt {1+x} \sqrt {1-x+x^2}} \\ & = \frac {2}{9 x^2 \sqrt {1+x} \sqrt {1-x+x^2} \left (1+x^3\right )}+\frac {\left (13 \sqrt {1+x^3}\right ) \int \frac {1}{x^3 \left (1+x^3\right )^{3/2}} \, dx}{9 \sqrt {1+x} \sqrt {1-x+x^2}} \\ & = \frac {26}{27 x^2 \sqrt {1+x} \sqrt {1-x+x^2}}+\frac {2}{9 x^2 \sqrt {1+x} \sqrt {1-x+x^2} \left (1+x^3\right )}+\frac {\left (91 \sqrt {1+x^3}\right ) \int \frac {1}{x^3 \sqrt {1+x^3}} \, dx}{27 \sqrt {1+x} \sqrt {1-x+x^2}} \\ & = \frac {26}{27 x^2 \sqrt {1+x} \sqrt {1-x+x^2}}+\frac {2}{9 x^2 \sqrt {1+x} \sqrt {1-x+x^2} \left (1+x^3\right )}-\frac {91 \left (1+x^3\right )}{54 x^2 \sqrt {1+x} \sqrt {1-x+x^2}}-\frac {\left (91 \sqrt {1+x^3}\right ) \int \frac {1}{\sqrt {1+x^3}} \, dx}{108 \sqrt {1+x} \sqrt {1-x+x^2}} \\ & = \frac {26}{27 x^2 \sqrt {1+x} \sqrt {1-x+x^2}}+\frac {2}{9 x^2 \sqrt {1+x} \sqrt {1-x+x^2} \left (1+x^3\right )}-\frac {91 \left (1+x^3\right )}{54 x^2 \sqrt {1+x} \sqrt {1-x+x^2}}-\frac {91 \sqrt {2+\sqrt {3}} \sqrt {1+x} \sqrt {\frac {1-x+x^2}{\left (1+\sqrt {3}+x\right )^2}} F\left (\sin ^{-1}\left (\frac {1-\sqrt {3}+x}{1+\sqrt {3}+x}\right )|-7-4 \sqrt {3}\right )}{54 \sqrt [4]{3} \sqrt {\frac {1+x}{\left (1+\sqrt {3}+x\right )^2}} \sqrt {1-x+x^2}} \\ \end{align*}
Result contains complex when optimal does not.
Time = 10.43 (sec) , antiderivative size = 183, normalized size of antiderivative = 0.90 \[ \int \frac {1}{x^3 (1+x)^{5/2} \left (1-x+x^2\right )^{5/2}} \, dx=\frac {-\frac {6 \left (27+130 x^3+91 x^6\right )}{x^2 (1+x)^{3/2}}-\frac {91 i (1+x) \left (1-x+x^2\right ) \sqrt {6+\frac {36 i}{\left (-3 i+\sqrt {3}\right ) (1+x)}} \sqrt {1-\frac {6 i}{\left (3 i+\sqrt {3}\right ) (1+x)}} \operatorname {EllipticF}\left (i \text {arcsinh}\left (\frac {\sqrt {-\frac {6 i}{3 i+\sqrt {3}}}}{\sqrt {1+x}}\right ),\frac {3 i+\sqrt {3}}{3 i-\sqrt {3}}\right )}{\sqrt {-\frac {i}{3 i+\sqrt {3}}}}}{324 \left (1-x+x^2\right )^{3/2}} \]
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Time = 0.68 (sec) , antiderivative size = 179, normalized size of antiderivative = 0.88
method | result | size |
elliptic | \(\frac {\sqrt {\left (1+x \right ) \left (x^{2}-x +1\right )}\, \left (-\frac {\sqrt {x^{3}+1}}{2 x^{2}}-\frac {2 x}{9 \left (x^{3}+1\right )^{\frac {3}{2}}}-\frac {32 x}{27 \sqrt {x^{3}+1}}-\frac {91 \left (\frac {3}{2}-\frac {i \sqrt {3}}{2}\right ) \sqrt {\frac {1+x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x -\frac {1}{2}-\frac {i \sqrt {3}}{2}}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x -\frac {1}{2}+\frac {i \sqrt {3}}{2}}{-\frac {3}{2}+\frac {i \sqrt {3}}{2}}}\, F\left (\sqrt {\frac {1+x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \sqrt {\frac {-\frac {3}{2}+\frac {i \sqrt {3}}{2}}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{54 \sqrt {x^{3}+1}}\right )}{\sqrt {1+x}\, \sqrt {x^{2}-x +1}}\) | \(179\) |
default | \(\frac {91 i \sqrt {3}\, F\left (\sqrt {-\frac {2 \left (1+x \right )}{-3+i \sqrt {3}}}, \sqrt {-\frac {-3+i \sqrt {3}}{i \sqrt {3}+3}}\right ) x^{5} \sqrt {-\frac {2 \left (1+x \right )}{-3+i \sqrt {3}}}\, \sqrt {\frac {i \sqrt {3}-2 x +1}{i \sqrt {3}+3}}\, \sqrt {\frac {i \sqrt {3}+2 x -1}{-3+i \sqrt {3}}}-273 F\left (\sqrt {-\frac {2 \left (1+x \right )}{-3+i \sqrt {3}}}, \sqrt {-\frac {-3+i \sqrt {3}}{i \sqrt {3}+3}}\right ) x^{5} \sqrt {-\frac {2 \left (1+x \right )}{-3+i \sqrt {3}}}\, \sqrt {\frac {i \sqrt {3}-2 x +1}{i \sqrt {3}+3}}\, \sqrt {\frac {i \sqrt {3}+2 x -1}{-3+i \sqrt {3}}}+91 i \sqrt {-\frac {2 \left (1+x \right )}{-3+i \sqrt {3}}}\, \sqrt {\frac {i \sqrt {3}-2 x +1}{i \sqrt {3}+3}}\, \sqrt {\frac {i \sqrt {3}+2 x -1}{-3+i \sqrt {3}}}\, F\left (\sqrt {-\frac {2 \left (1+x \right )}{-3+i \sqrt {3}}}, \sqrt {-\frac {-3+i \sqrt {3}}{i \sqrt {3}+3}}\right ) \sqrt {3}\, x^{2}-273 \sqrt {-\frac {2 \left (1+x \right )}{-3+i \sqrt {3}}}\, \sqrt {\frac {i \sqrt {3}-2 x +1}{i \sqrt {3}+3}}\, \sqrt {\frac {i \sqrt {3}+2 x -1}{-3+i \sqrt {3}}}\, F\left (\sqrt {-\frac {2 \left (1+x \right )}{-3+i \sqrt {3}}}, \sqrt {-\frac {-3+i \sqrt {3}}{i \sqrt {3}+3}}\right ) x^{2}-182 x^{6}-260 x^{3}-54}{108 x^{2} \left (x^{2}-x +1\right )^{\frac {3}{2}} \left (1+x \right )^{\frac {3}{2}}}\) | \(481\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.08 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.31 \[ \int \frac {1}{x^3 (1+x)^{5/2} \left (1-x+x^2\right )^{5/2}} \, dx=-\frac {{\left (91 \, x^{6} + 130 \, x^{3} + 27\right )} \sqrt {x^{2} - x + 1} \sqrt {x + 1} + 91 \, {\left (x^{8} + 2 \, x^{5} + x^{2}\right )} {\rm weierstrassPInverse}\left (0, -4, x\right )}{54 \, {\left (x^{8} + 2 \, x^{5} + x^{2}\right )}} \]
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\[ \int \frac {1}{x^3 (1+x)^{5/2} \left (1-x+x^2\right )^{5/2}} \, dx=\int \frac {1}{x^{3} \left (x + 1\right )^{\frac {5}{2}} \left (x^{2} - x + 1\right )^{\frac {5}{2}}}\, dx \]
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\[ \int \frac {1}{x^3 (1+x)^{5/2} \left (1-x+x^2\right )^{5/2}} \, dx=\int { \frac {1}{{\left (x^{2} - x + 1\right )}^{\frac {5}{2}} {\left (x + 1\right )}^{\frac {5}{2}} x^{3}} \,d x } \]
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\[ \int \frac {1}{x^3 (1+x)^{5/2} \left (1-x+x^2\right )^{5/2}} \, dx=\int { \frac {1}{{\left (x^{2} - x + 1\right )}^{\frac {5}{2}} {\left (x + 1\right )}^{\frac {5}{2}} x^{3}} \,d x } \]
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Timed out. \[ \int \frac {1}{x^3 (1+x)^{5/2} \left (1-x+x^2\right )^{5/2}} \, dx=\int \frac {1}{x^3\,{\left (x+1\right )}^{5/2}\,{\left (x^2-x+1\right )}^{5/2}} \,d x \]
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